For which of the following sets of quantum numbers,an electron will have the highest energy?

  • A
    $n=3, l=2, m=1, s=-1/2$
  • B
    $n=4, l=3, m=-1, s=+1/2$
  • C
    $n=4, l=1, m=-1, s=+1/2$
  • D
    $n=5, l=0, m=0, s=-1/2$

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Which of the following sets of quantum numbers is allowed?

Arrange the following atomic orbitals of multi-electron atoms in order of increasing energy.
$A$. $n=3, l=2, m=+1$
$B$. $n=4, l=0, m=0$
$C$. $n=6, l=1, m=0$
$D$. $n=5, l=1, m=+1$
$E$. $n=2, l=1, m=+1$
Choose the correct answer from the options given below:

For the given quantum numbers $n$ and $l$ of electrons:
$(i) n = 4, l = 1$
$(ii) n = 4, l = 0$
$(iii) n = 3, l = 2$
$(iv) n = 3, l = 1$
Arrange them in the increasing order of their energy.

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